Great rhombicosidodecahedron

The great rhombicosidodecahedron or grid, also commonly known as the (rhombi)truncated icosidodecahedron, is the most complex of the 13 Archimedean solids. It consists of 12 decagons, 20 hexagons, and 30 squares, with one of each type of face meeting per vertex. It can be obtained by cantitruncation of the dodecahedron or icosahedron, or equivalently by truncating the vertices of an icosidodecahedron and then adjusting the edge lengths to be all equal.

This is one of three Wythoffian non-prismatic polyhedra whose Coxeter diagram nodes are all ringed, the other two being the great rhombitetratetrahedron and the great rhombicuboctahedron.

It can be alternated into the snub dodecahedron after edge lengths are equalized.

Vertex coordinates
A great rhombicosidodecahedron of edge length 1 has vertex coordinates given by all permutations of along with all even permutations of:
 * $$\left(±\frac12,\,±\frac12,\,±\frac{3+2\sqrt5}{2}\right),$$
 * $$\left(±\frac12,\,±\frac{2+\sqrt5}{2},\,±\frac{4+\sqrt5}{2}\right),$$
 * $$\left(±1,\,±\frac{3+\sqrt5}{4},\,±\frac{7+3\sqrt5}{4}\right),$$
 * $$\left(±\frac{3+\sqrt5}{4},\,±3\frac{1+\sqrt5}{4},\,±\frac{3+\sqrt5}{2}\right),$$
 * $$\left(±\frac{1+\sqrt5}{2},\,±\frac{5+3\sqrt5}{4},\,±\frac{5+\sqrt5}{4}\right).$$

Representations
A great rhombicosidodecahedron has the following Coxeter diagrams:


 * x5x3x (full symmetry)
 * xuxxuAxFVFxx5xxFVFxAuxxux&#xt (H2 axial, decagon-first)

Semi-uniform variant
The great rhombicosidodecahedron has a semi-uniform variant of the form x5y3z that maintains its full symmetry. This variant has 12 dipentagons, 20 ditrigons, and 30 rectangles as faces.

With edges of length a (dipentagon-rectangle), b (dipentagon-ditrigon), and c (ditrigon-rectangle), its circumradius is given by $$\sqrt{\frac{9a^2+12b^2+5c^2+16ab+8ac+12bc+(3a^2+4b^2+c^2+8ab+4ac+4bc)\sqrt5}{8}}$$ and its volume is given by $$\frac{15a^3+60a^2b+45a^2c+60ab^2+60abc+15ac^2+30b^3+60b^2c+30bc^2+5c^3}{4}+(21a^3+72a^2b+45a^2c+108ab^2+180abc+45ac^2+34b^3+60b^2c+30bc^2+5c^3)\frac{\sqrt5}{12}$$.