Small dodecacronic hexecontahedron

The small dodecacronic hexecontahedron is a uniform dual polyhedron. It consists of 60 darts.

It appears the same as the small rhombidodecacron.

If its dual, the small dodecicosidodecahedron, has an edge length of 1, then the short edges of the darts will measure $$2\frac{\sqrt{65+19\sqrt5}}{11} ≈ 1.88500$$, and the long edges will be $$2\frac{\sqrt{2\left(5+2\sqrt5\right)}}{3} ≈ 2.90167$$. ​The dart faces will have length $$\frac{\sqrt{10\left(157+31\sqrt5\right)}}{33} ≈ 1.44160$$, and width $$\sqrt5+1 ≈ 3.23607$$. ​The darts have two interior angles of $$\arccos\left(\frac58+\frac{\sqrt5}{8}\right) ≈ 25.24283°$$, one of $$\arccos\left(-\frac18+\frac{9\sqrt5}{40}\right) ≈ 67.78301°$$, and one of $$360°-\arccos\left(-\frac14-\frac{\sqrt5}{10}\right) ≈ 241.73132°$$.

Vertex coordinates
A small dodecacronic hexecontahedron with dual edge length 1 has vertex coordinates given by all even permutations of:
 * $$\left(±\frac{3+\sqrt5}{2},\,±\frac{1+\sqrt5}{2},\,0\right),$$
 * $$\left(±\frac{15+\sqrt5}{22},\,±\frac{25+9\sqrt5}{22},\,0\right),$$
 * $$\left(±\frac{5+3\sqrt5}{6},\,±\frac{5+\sqrt5}{6},\,0\right),$$
 * $$\left(±\frac{5+4\sqrt5}{11},\,±\frac{5+4\sqrt5}{11},\,±\frac{5+4\sqrt5}{11}\right).$$