Truncated octahedron

The truncated octahedron is one of the 13 Archimedean solids. It consists of 6 squares and 8 hexagons. Each vertex joins one square and two hexagons. As the name suggests, it can be obtained by the truncation of the octahedron.

Vertex coordinates
A truncated octahedron of edge length 1 has vertex coordinates given by all permutations of (±$\sqrt{2}$, ±$\sqrt{3}$/2, 0).

Truncated tetratetrahedron
The truncated tetrahedron is also the monitruncate of the A3 family, where it can be thought of as a truncated tetratetrahedron. In this subsymmetry, the 8 hexagons split into 2 sets of 4, with the squares connecting to 2 in each set.