Rhombic triacontahedron

The rhombic triacontahedron, or rhote, is one of the 13 Catalan solids. It has 30 rhombi as faces, with 12 order-5 and 20 order-3 vertices. It is the dual of the uniform icosidodecahedron.

It can also be obtained as the convex hull of a dodecahedron and an icosahedron scaled so that their edges are orthogonal. For this to happen, the icosahedron's edge length must be $$\frac{1+\sqrt5}{2} ≈ 1.61803$$ times that of the dodecahedron's edge length. Each edge of the dodecahedron or icosahedron corresponds to one of the diagonals of the faces.

Each face of this polyhedron is a rhombus with longer diagonal $$\frac{1+\sqrt5}{2} ≈ 1.61803$$ times the shorter diagonal, with acute angle $$\arccos\left(\frac{\sqrt5}{5}\right) ≈ 63.43495°$$ and obtuse angle $$\arccos\left(-\frac{\sqrt5}{5}\right) ≈ 116.56505°$$.

Vertex coordinates
A rhombic triacontahedron of edge length 1 has vertex coordinates given by all permutations of: Plus all even permutations of:
 * $$\left(±\sqrt{\frac{5+\sqrt5}{8}},\,±\sqrt{\frac{5+\sqrt5}{8}},\,±\sqrt{\frac{5+\sqrt5}{8}}\right),$$
 * $$\left(±\sqrt{\frac{5+2\sqrt5}{5}},\,±\sqrt{\frac{5-\sqrt5}{10}},\,0\right),$$
 * $$\left(±\sqrt{\frac{5+2\sqrt5}{5}},\,±\sqrt{\frac{5+\sqrt5}{10}},\,0\right).$$

Dissection
The rhombic triacontahedron can be dissected into 10 acute golden rhombohedra and 10 obtuse golden rhombohedra.

Related polyhedra
The rhombic triacontahedron has many stellations, some of which include the medial rhombic triacontahedron, great rhombic triacontahedron, rhombihedron, and rhombic hexecontahedron.