Bitetrahedral diacositetracontachoron

The bitetrahedral diacositetracontachoron or bittid is a convex isogonal polychoron that consists of 720 tetragonal disphenoids and 1440 phyllic disphenoids. However, it cannot be made uniform. It is the second in a series of isogonal icosidodecahedral swirlchora.

The ratio between the longest and shortest edges is 1:$$\frac{\sqrt{54+6\sqrt{37+8\sqrt{10}}}}{6}$$ ≈ 1:1.67794.

Vertex coordinates
Vertex coordinates for a bitetrahedral diacositetracontachoron, created from the vertices of a hexacosichoron of edge length 1, are given by all permutations and sign changes of: as well as all even permutations and all sign changes of: as well as all permutations and even sign changes of: as well as all permutations and odd sign changes of:
 * (0, 0, 0, (1+$\sqrt{5}$)/2),
 * ((1+$\sqrt{5}$)/4, (1+$\sqrt{5}$)/4, (1+$\sqrt{5}$)/4, (1+$\sqrt{5}$)/4),
 * (0, 0, $\sqrt{3+√5}$/2, $\sqrt{3+√5}$/2),
 * (0, 1/2, (1+$\sqrt{5}$)/4, (3+$\sqrt{5}$)/4),
 * ($\sqrt{2}$/4, $\sqrt{2}$/4, $\sqrt{2}$/4, $\sqrt{18+8√5}$/4),
 * ($\sqrt{3-√5}$/4, $\sqrt{7+3√5}$/4, $\sqrt{7+3√5}$/4, $\sqrt{7+3√5}$/4),
 * ($\sqrt{3+√5}$/4, $\sqrt{3+√5}$/4, $\sqrt{3+√5}$/4, $\sqrt{15+5√5}$/4).

Isogonal derivatives
Substitution by vertices of these following elements will produce these convex isogonal polychora:
 * Rhombic disphenoid (720): Snub bitetrahedral diacositetracontachoron