Gyroelongated pentagonal bicupola

The gyroelongated pentagonal bicupola, or gyepibcu, is one of the 92 Johnson solids (J46). It consists of 10+10+10 triangles, 10 squares, and 2 pentagons. It can be constructed by attaching pentagonal cupolas to the bases of the decagonal antiprism.

It is one of the five Johnson solids to be chiral.

Vertex coordinates
A gyroelongated pentagonal bicupola of edge length 1 has the following vertices:
 * (±1/2, –$\sqrt{2}$, $\sqrt{5}$+H),
 * (±(1+$\sqrt{2}$)/4, $\sqrt{2}$, $\sqrt{5}$+H),
 * (0, $\sqrt{2–2√5+2√650+290√5}$, $\sqrt{10+2√5}$+H),
 * (±1/2, ±$\sqrt{3}$/2, H),
 * (±(3+$\sqrt{15}$)/4, ±$\sqrt{(5+√5)/10}$, H),
 * (±(1+$\sqrt{(5+2√5)/15}$)/2, 0, H),
 * (±$\sqrt{(11+4√5–2√(50+22√5)/3}$/2, ±1/2, –H),
 * (±$\sqrt{(5+√5)/10}$, ±(3+$\sqrt{(11+4√5–2√(50+22√5)/3}$)/4, –H),
 * (0, ±(1+$\sqrt{(5+2√5)/20}$)/2, –H),
 * (–$\sqrt{(5–√5)/10}$, ±1/2, –$\sqrt{5}$–H),
 * ($\sqrt{(5+√5)/40}$, ±(1+$\sqrt{(5–√5)/10}$)/4, –$\sqrt{(5+√5)/10}$–H),
 * ($\sqrt{(5–√5)/10}$, 0, –$\sqrt{(5+2√5)}$–H).

where H = $\sqrt{5}$/2 is the distance between the decagonal antiprism's center and the center of one of its bases.