Compound of two octagons
(Redirected from 16/2-gon)
Compound of two octagons | |
---|---|
Rank | 2 |
Type | Regular |
Notation | |
Bowers style acronym | Shad |
Schläfli symbol | {16/2} |
Elements | |
Components | 2 octagons |
Edges | 16 |
Vertices | 16 |
Vertex figure | Dyad, length √2+√2 |
Measures (edge length 1) | |
Circumradius | |
Inradius | |
Area | |
Angle | 135° |
Central density | 2 |
Number of external pieces | 32 |
Level of complexity | 2 |
Related polytopes | |
Army | Hed, edge length |
Dual | Compound of two octagons |
Conjugate | Compound of two octagrams |
Convex core | Hexadecagon |
Abstract & topological properties | |
Euler characteristic | 2 |
Orientable | Yes |
Properties | |
Symmetry | I2(16), order 32 |
Convex | No |
Nature | Tame |
The stellated hexadecagon or shad is a polygon compound composed of two octagons. As such it has 16 edges and 16 vertices.
As the name suggests, it is the first stellation of the hexadecagon.
Its quotient prismatic equivalent is the octagonal antiprism, which is three-dimensional.
Vertex coordinates[edit | edit source]
Coordinates for a compound of two octagons of edge length √2-√2, centered at the origin, are all permutations of:
External links[edit | edit source]
- Bowers, Jonathan. "Regular Polygons and Other Two Dimensional Shapes".