# Triangular tegum

(Redirected from Triangular bipyramid)
Triangular tegum Rank3
TypeCRF
SpaceSpherical
Bowers style acronymTrit
Info
Coxeter diagramoxo3ooo&#xt
SymmetryA2×A1, order 12
ArmyTrit
RegimentTrit
Elements
Vertex figures2 triangles, edge length 1
3 rhombi, edge length 1
Faces6 triangles
Edges3+6
Vertices2+3
Measures (edge length 1)
Inradius$\frac{\sqrt6}{9} ≈ 0.27217$ Volume$\frac{\sqrt2}{6} ≈ 0.23570$ Dihedral angles3–3 equatorial: $\arccos\left(-\frac79\right) ≈ 141.05756°$ 3–3 pyramidal: $\arccos\left(\frac13\right) ≈ 70.52878°$ Height$\frac{2\sqrt6}{3} ≈ 1.63299$ Central density1
Euler characteristic2
Related polytopes
DualSemi-uniform Triangular prism
ConjugateTriangular tegum
Properties
ConvexYes
OrientableYes
NatureTame

The triangular tegum, or trit, also called a triangular bipyramid, triangular dipyramid or tridpy, is one of the 92 Johnson solids (J12). It has 6 equilateral triangles as faces, with 2 order-3 and 3 order-4 vertices. It can be constructed by joining two regular tetrahedra at one of their faces.

It is one of three regular polygonal tegums to be CRF. The others are the regular octahedron (square tegum) and the pentagonal tegum.

## Vertex coordinates

A triangular tegum of edge length 1 has the following vertices:

• $\left(±\frac{1}{2},\,-\frac{\sqrt3}{6},\,0\right),$ • $\left(0,\,\frac{\sqrt3}{3},\,0\right),$ • $\left(0,\,0,\,±\frac{\sqrt6}{3}\right).$ ## Representations

A triangular tegum has the following Coxeter diagrams:

• oxo3ooo&#xt (as tower)
• yo ox3oo&#zx (y = 26/3, as tegum product)
• oyo oox&#xt (digonal symmetry)

## Variations

The triangular tegum can have the height of its pyramids varied while maintaining its full symmetry These variations generally have 6 isosceles triangles for faces.

One notable variations can be obtained as the dual of the uniform triangular prism, which can be represented by m2m3o. In this variant the side edges are exactly $\frac23$ times the length of the edges of the base triangle, and all the dihedral angles are $\arccos\left(-\frac17\right) ≈ 98.21321°$ . Each face has apex angle $\arccos\left(-\frac18\right) \approx 97.18076°$ and base angles $\arccos\left(\frac34\right) \approx 41.40962°$ . If the base triangle has edge length 1, its height is $\frac23 ≈ 0.66667$ .

A triangular tegum with base edges of length b and side edges of length l has volume given by $\frac{\sqrt3b^2}{6}\sqrt{l^2-\frac{b^2}{3}}$ .

## Other triangular bipyramids

Besides this fully symmetric version, other 5-vertex polyhedra with 6 triangular faces exist:

## Related polyhedra

A triangular prism can be inserted between the halves of the triangular tegum to produce the elongated triangular bipyramid. Trying to insert a regular octahedron (as a triangular antiprism) would result in pairs of triangles becoming coplanar and turning into 60°/120° rhombi, resulting in a triangular antitegum, a variant of the cube.