|Bowers style acronym||Toe|
|Coxeter diagram||o4x3x ()|
|Faces||6 squares, 8 hexagons|
|Vertex figure||Isosceles triangle, edge lengths √, √, √ |
|Measures (edge length 1)|
|Number of external pieces||14|
|Level of complexity||3|
|Abstract & topological properties|
|Symmetry||B3, order 48|
The truncated octahedron or toe is one of the 13 Archimedean solids. It consists of 6 squares and 8 ditrigons. Each vertex joins one square and two hexagons. As the name suggests, it can be obtained by the truncation of the octahedron. It is also the omnitruncate of the tetrahedral family.
It is the only Archimedean solid that can tile 3D space by itself. This results in the bitruncated cubic honeycomb.
It can be alternated into the icosahedron after all edge lengths are made equal.
It is the 4th-order permutohedron.
Vertex coordinates[edit | edit source]
A truncated octahedron of edge length 1 has vertex coordinates given by all permutations of
Representations[edit | edit source]
A truncated octahedron has the following Coxeter diagrams:
- o4x3x () (full symmetry)
- x3x3x () (A3 symmetry, as great rhombitetratetrahedron)
- s4x3x () (as hexagon-alternated great rhombicuboctahedron)
- xuxux4ooqoo&#xt (B2 axial, square-first)
- xxux3xuxx&#xt (A2 axial, hexagon-first)
- Qqo xux4ooq&#zx (B2×A1 symmetry)
- xu(wx)(wx)ux oq(oQ)(oQ)qo&#xt (K2 axial, edge-first)
- xu(xd)ux xu(dx)ux&#xt (square-first when seen as rectangle)
Semi-uniform variant[edit | edit source]
With edges of length a (between two ditrigons) and b (between a ditrigon and a square), its circumradius is given by and its volume is given by .
Generally, alternating these polyhedra gives a pyritohedral icosahedron.
It has coordinates given by all permutations of:
[edit | edit source]
- Bowers, Jonathan. "Polyhedron Category 2: Truncates" (#12).
- Klitzing, Richard. "toe".
- Quickfur. "The Truncated Octahedron".
- Hi.gher.Space Wiki Contributors. "Octahedral truncate".